find the minimum value of
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y = sin 2x - √3 cos 2x
= 2*((1/2) sin2x - (√3/2)cos2x)
= 2*(cos(π/3) sin2x - sin(π/3) cos2x)
= 2*sin(2x - π/3)
now, minimum value of sin is -1 when angle is 3π/2
so minimum value of y is -2.
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