Math, asked by satardekar100, 4 months ago

find the minimum value of 4x2+1/x

Answers

Answered by deadpool132

2

Answer:

For a general quadratic equation ax

2

+bx+c=0,wherea>0theminimumvalueofexpressionoccursat

4a

−D

∴4x

2

+2x+1

minimumvalue=

4.4

−(2

2

−4.4.1)

=

16

12

=

4

3

Step-by-step explanation:

Please mark me Brailient

Answered by sumanmaurya1181

0

Answer:

4x2+1/x

4x2=1/x

4x^2+2x

2x

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