Find the minimum value of 5cosA + 12sinA + 12 .
i will give you 5 star.please answer
Ugoel911:
Answer is -1 since acosA+bsinA has least value -rt((a)sq+(b)sq). Hence ans will be -13+12= -1
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ANSWER
Given=
>5cosA + 12sinA + 12
=>13{ + } + 12
Let, Cos
then Sin
So we get =>
=>13(CosA × ) +12
=>13{Cos}
Here the minimum value of {Cos} is -1.
Hence the minimum value of 5cosA + 12sinA + 12 will be -13 + 12=-1.
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