Math, asked by mark578, 1 year ago

Find the minimum value of 5cosA + 12sinA + 12 .

i will give you 5 star.please answer


Ugoel911: Answer is -1 since acosA+bsinA has least value -rt((a)sq+(b)sq). Hence ans will be -13+12= -1

Answers

Answered by anonymous692
1
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Answered by generalRd
1

ANSWER

Given=

>5cosA + 12sinA + 12

=>13{\dfrac{5}{13}CosA + \dfrac{12}{13}SinA} + 12

Let, Cos \theta=\dfrac{5}{13}

then Sin\theta=\dfrac{12}{13}

So we get =>

=>13(CosA × Cos\theta + SinA \times Sin\theta) +12

=>13{Cos(A - \theta)}

Here the minimum value of {Cos(A -\theta )} is -1.

Hence the minimum value of 5cosA + 12sinA + 12 will be -13 + 12=-1.

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