Question

Find the minimum value of 5cosA + 12sinA + 12.
Solve this it's urgent

Answer 1

Dear mate,
Kindly mark the answer as brainliest if you find it useful.

Here's what you were looking for:

Your expression is 5cosA+12sinA+12

See, the minimum value of sin(x) and cos(x) is -1 for both ( and ofcourse the maximum value is +1)

So for the expression to take minimum value, sin(x) and cos(x) must take their minimum value i.e. -1.

So substituting that in the eqn we get,
-5 -12 +12
Which gives the answer -5.

Hope this clears your doubt.✌

Answer 2

SWER

Given=

>5cosA + 12sinA + 12

=>13{$\dfrac{5}{13}CosA$ + $\dfrac{12}{13}SinA$} + 12

Let, Cos $\theta=\dfrac{5}{13}$

then Sin$\theta=\dfrac{12}{13}$

So we get =>

=>13(CosA × $Cos\theta + SinA \times Sin\theta$) +12

=>13{Cos$(A - \theta)$}

Here the minimum value of {Cos$(A -\theta )$} is -1.

Hence the minimum value of 5cosA + 12sinA + 12 will be -13 + 12=-1.