Math, asked by prityranigiri, 1 month ago

Find the minimum value of 5sinx+12cosx

Answers

Answered by ayesha513

0

Step-by-step explanation:

Minimum value of x is 0°

= so,

=5×sinx+12cosx

=5×sin0°+12cos0°

=5×0+12×1

=10+12=12

Hence, minimum value is 12.

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