Math, asked by abhinavpandey8080, 9 months ago

Find the minimum value of (a^2+a+1)(b^2 +b+1)(c^2+c+1)/3abc​

Answers

Answered by vedantvispute38
0

Step-by-step explanation:

 \frac{( {a}^{2} + a)( {b}^{2} + b)( {c}^{2}   + c) }{3abc}

a(a + 1)b(b + 1)c(c + 1) \times  \frac{1}{3abc}

 \frac{(a + 1)(b + 1)(c + 1)}{3}  \\

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