Question

Find the minimum value of (ax+by), where xy = c^2​

Answer 1

Answer:

Solution. ∴x=c√ba ∴ x = c b a is the point of minima. ∴x=−c√ba ∴ x = − c b a is the point of maxima. Thus, the minimum value of (ax + by), where xy = c2 is 2c√ab 2 c a b .