Math, asked by adnankasmani46, 3 months ago

find the minimum value of f(x,y)=x²+y²+6x+12

Answers

Answered by sukhmeet478409

1

Answer:

minimum value of f(x,y)=x2 + y2 + 6x + 12. hence. f(x,y) has minimum value at (-3,0), which is f(x,y) = 12 + 9 – 18 = 3.

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