Question

Find the minimum value of ‘ K ‘ in the quadratic equation x2

+ 4x + K = 0,

at which the roots of the equation change from real to imaginary.​

Answer 1

Answer:

Step-by-step explanation:

b = 4 , c = k and a = 1

FOR ROOTS TO BE IMAGINARY:-

D < 0

D = b² - 4ac

4² - 4 x 1 x k < 0

16 - 4k < 0

16 < 4k

k > 4

so k should be greater than 4.

PLZ MARK IT AS BRAINLIST!!!!!!!!!

Answer 2

Step-by-step explanation:

For roots to be imaginary

b=4,a=1,c=k

D=b^2-4ac

= 4^2-4×1×k

= 16-4k is less than 0

then,

16 is greater than 4k

and k is greater than 4

For any value of k should be greater than 4

It helps you dude...