Math, asked by NilotpalSwargiary, 7 months ago

Find the minimum value of the following expression:
3 {x}^{2} + 4x + 7

Answers

Answered by dangerousqueen01
1

Answer:

Step-by-step explanation:

3 {x}^{2}  + 4x + 7 \\  = 3 {x}^{2} + (3 + 7)x + 7 \\  = 3 {x}^{2}   + 3x + 7x + 7 \\  = 3x(x + 1) + 7(x + 1) \\  = (x + 1)(3x + 7)

Answered by Anonymous
0

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$$\begin{lgathered}3 {x}^{2} + 4x + 7 \\ = 3 {x}^{2} + (3 + 7)x + 7 \\ = 3 {x}^{2} + 3x + 7x + 7 \\ = 3x(x + 1) + 7(x + 1) \\ = (x + 1)(3x + 7)\end{lgathered}$$

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