Find the minimum value of |x-2|+|x+2|
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When X = 1
|X| = 1
|X-1| = 0
|X-2| = 1
|X-3| = 2
Now,
|X| + |X-1| + |X-2| + |X-3| = 1 + 0 + 1 +2 = 4
Similarly , When X = 2
|X| = 2
|X-1| = 1
|X-2| = 0
|X-3| = 1
Now,
|X| + |X-1| + |X-2| + |X-3| = 2 + 1 + 0 + 1 = 4
When X = 0
|X| = 0
|X-1| = 1
|X-2| = 2
|X-3| = 3
Now,
|X| + |X-1| + |X-2| + |X-3| = 0 + 1 + 2 + 3 = 6
When X = 3
|X| = 3
|X-1| = 2
|X-2| = 1
|X-3| = 0
Now,
|X| + |X-1| + |X-2| + |X-3| = 3 + 2 + 1 + 0 = 6
Hence the minimum value is 4 at x = 1 and at x = 2
Maximum value is 6 at x = 0 and at x = 3
Hope it helps you dear
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