Find the missing angle of the following quadrilaterals
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5
ans 1
105° + 80° + 45° +2x-5 = 360°
225° + 2x = 360°
2x = 360 - 225
2x = 135
x =
ans 2
60° + 120° + 110° + x = 360°
290° + x = 360
x = 360 - 290
x = 70
pls mark me as brainliest
105° + 80° + 45° +2x-5 = 360°
225° + 2x = 360°
2x = 360 - 225
2x = 135
x =
ans 2
60° + 120° + 110° + x = 360°
290° + x = 360
x = 360 - 290
x = 70
pls mark me as brainliest
Aishalove:
Thanks
Answered by
3
Q.2
60+110+120+x=360
290+x=360
x=360-290
x=70
60+110+120+x=360
290+x=360
x=360-290
x=70
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