Question

find the missing angles in each of the following

Answer 1

Answer:

In

Quadrilateral KLMN

we know sum of all interior angles of a quadrilateral=360°

therefore

x+10+91+x+70+89=360°

2x+260=260

2x=360-260

2x=100

x=100/2

x=50°

therefore the missing angles are

x+10=50+10=60°

x+70=50+70=120°

In

Quadrilateral JKLM

we know sum of all interior angles of a quadrilateral=360°

therefore

x+120+50+70+x+60=360°

2x+300=360

2x=360-300=60

x=60/2

x=30°

therefore the missing angles are

x+120=150°

x+60=90°

hope it helps

Answer 2

Answer:

1) x+10+91+89+x+70=360 ( All angles of a quadrilateral add up to 360)

2x+180+80=360

2x= 360-260

x= 100/2

x=50

2)x+120+50+x+60+70= 360 ( All angles of a quadrilateral add up to 360)

Therefore, 2x+300=360

2x= 360-300

x= 60/2

x= 30