Question

Find the missing frequencies and the median for the following distribution if the mean is 1.46.
No. of accidents:
0
1
2
3
4
5
Frequency:
46
?
?
25
10
5
Total 200

Answer 1

SOLUTION :  

CUMULATIVE FREQUENCY TABLE are in the attachment.  

Let the missing frequencies be  x and y.

Given : n(Σfi) = 200 , Mean = 1.46

From the table, Σfi = 86 + x + y , Σfixi = 140 + x + 2y

Σfi = 86 + x + y

200 = 86 + x + y

200 - 86 = x + y

x + y = 114

x = 114 - y …………(1)

MEAN = Σfixi/ Σfi

1.46 = (140 + x + 2y) / 200

1.46 × 200 = (140 + x + 2y)

292 = (140 + x + 2y)

x + 2y = 292 - 140

x + 2y = 152 ……….(2)

114 - y + 2y = 152

[From eq 1]

114 + y = 152

y = 152 - 114

y = 38

Put the value of y in eq 1  

x = 114 - y

x = 114 - 38

x = 76  

Hence, the missing frequencies be  x = 76 and y = 38 .

FOR MEDIAN :  

Here, n = 200

n/2 = 100

Since, the Cumulative frequency just greater than 100 is 122 and the value corresponding to 122 is 1.  

Hence, the Median is 1.  

HOPE THIS ANSWER WILL HELP YOU.

Answer 2

Answer:

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