Find the missing frequencies f; and f, in table given below; it is being given that the mean of the
given frequency distribution is 50.
Class
0-20 20-40 40-60 60-80 80-100 Total
Frequency 17
fi
32
f2
19
120
Answers
Answered by
0
Answer:
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Answered by
0
Answer:
0−20 10 17 170
20−40 30 f
1
30f
1
40−60 50 32 1600
60−80 70 f
2
70f
2
80−100 90 19 1710
∑f
i
=f
1
+f
2
+68 ∑f
i
x
i
=3480+30f
1
+70f
2
∑f
i
=120 [ Given ]
∑f
i
=f
1
+f
2
+68
120=f
1
+f
2
+68
∴ f
1
+f
2
=52
⇒ f
1
=52−f
2
---- ( 1 )
⇒ Mean(
x
)=
∑f
i
∑f
i
x
i
⇒ 50=
120
3480+30f
1
+70f
2
⇒ 6000=3480+30(52−f
2
)+70f
2
[ From ( 1 ) ]
⇒ 2520=1560−30f
2
+70f
2
⇒ 40f
2
=960
∴ f
2
=24
Substituting value of f
2
in ( 1 )
f
1
=52−24=28
∴ f
1
=28,f
2
=24
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