Question

Find the missing frequencies f1 and f2 in the following frequency distribution, if it is known hat the mean of the distribution is 1.46 :

x1 0 1 2 3 4 5 total
f2 46 f1 f2 25 10 5 200

Answer 1

x1 f x1f
0 46 0
1 f1 f1
2 f2 2f2
3 25 75
4 10 40
5 5 25
=86+f1+f2 =140+f1+2f2

since,€f=86+f1+f2
but,€f=200
so,86+f1+f2=200
f1+f2=114 (i)
now,mean=140+f1+2f2/86+f1+f2
=140+114+f2/86+114
=254+f2/200
but,mean=1.46
254+f2/200=1.46
254+f2=292
f2=38
putting f2=38 in eq.(i)
we get:f1=76

Answer 2

Here is your answer

Refer the following attachment

Hope it helps

Mark it as brainliest

Regards

Brainly user

KARAN