Find the missing frequencies fq, f, and f; in the
following frequency distribution, when it is given
that f2fz = 4:3, and mean = 50 [CBSE 2014]
Class interval
Frequency
0-20
20-40
40-60
60-80
80 - 100
Total
120
Answers
Answer:Class- Interval Mid value(V) Frequency() V F
0-20 10 17 170
20-40 30 f 1 30 f 1
40-60 50 f 2 50 f 2
60-80 70 f 3 70 f 3
80-100 90 19 1710
SUM(F)=120 SUM(VF)=Mean=50
1. 17+f 1+f 2+f 3+19= 120
→ f 1+f 2+f 3
= 120 - 36=84
→ f 2 : f 3 = 4 : 3
So,Let, f 2 and f 3 = 4 k and 3 k
→f 1 + 4 k + 3 k= 84
→→f 1 + 7 k= 84------(1)
2. 170 + 30 f 1 + 50 f 2 + 70 f 3 + 1710 = 50×120
→170 + 30 f 1 + 50 × 4 k + 70 × 3 k + 1710= 6000
→170 + 30 f 1 + 200 k + 210 k + 1710= 6000
→30 f 1 + 410 k= 4120
→→ 3 f 1 + 41 k = 412 ----(2)
→→f 1 + 7 k= 84------(1)
=3 × equation(1) - equation (2)
⇒21 k - 41 k = 252- 412
⇒- 20 k = - 160
⇒k=8
Substituting the value of k in equation (2)
→ f 1 +56=84
→ f 1 = 84-56
→ f 1= 28
→f 2 = 4 × 8= 32
→f 3 = 3 × 8 = 24
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Explanation: