Question

find the missing frequencies in the following distribution if it is known that the mean of the distribution is 1.46
no. of accidents (x) 0 1 2 3 4 5
frequency (f) 46 f1 f2 25 10 5 ​

Answer 1

Step-by-step explanation:

$</p><p>\huge\pink{A}\red{N}\purple{S}\blue{W}\orange{E}\green{R}$

$N=200    So, Median =2(2N)thobs+(2N+1)thobs</p><p>=2100thobs+101thobs=21+1=1</p><p>∴  Median = 1</p><p></p><p>$

Answer 2

hope it will help you

N=200 So, Median =2(2N)thobs+(2N+1)thobs < /p > < p > =2100thobs+101thobs=21+1=1 < /p > < p > ∴ Median = 1 < /p > < p > < /p > < p >N=200 So,Median =2(2N)thobs+(2N+1)thobs</p><p>=2100thobs+101thobs=21+1=1</p><p>∴ Median=1</p><p></p><p>

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