Find the missing frequency from the table if the median is 24
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Answer:
Let the missing frequency be x.
Age in years
(x) No. of persons
(f) C.F.
0-10 5 5
10-20 25 30
20-30 x 30 +x
30-40 18 48 +x
40-50 7 55 +x
N=55+x
As, N=55+x ⇒
2
N
=
2
55+x
Median=l+
f
2
N
+C
×h
As median is given 24, therefore median class is 20−30.
Therefore,
l=lower limit of median class =20
C=C.F. of the class preceding the median class =30
h= higher limit - lower limit =40−30=10
f=frequency of median class =x
∴median=20+
x
2
55+x
−30
×10
24=20+
2x
x−5
×10
4=
x
x−5
×5
⇒4x=5x−25
⇒x=25
Hence, the missing frequency is 25.
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