Question

Find the missing frequency if the median of the data is 46.... Class interval : 10-20,20-30,30-40,40-50,50-60,60-70,70-80 frequency : 12,30,f1,65,f2,25,18...sum of the frequency is 230 cumulative frequency: 12,42,42+f1,107+f1,107+f1+f2,132+f1+f2,150+f1+f2... respectively....plss answer quickly its very urgent I will mark the answer as brainliest if your answer is correct ....sure....

Answer 1

Answer:

Step-by-step explanation:

150 + f1 + f2 = 230

f1 + f2 = 80

median = $l + h (\frac{n/2-cf}{f} )$

median class = 40 - 50

l = 40

h = 10

n/2 = 115

cf = 42 + f1

f = 65

median = $40 + 10 (\frac{115 - 42 - f1}{65} )$

solving this

f1 = 34

f2 = 80 - f1 = 46