Find the missing frequency "x" of the following distribution if mode is 34.5- Marks Obtained 0-10 10-20 20-30 30-40 40-50 and the No. of students are 4 ,8 ,10, x, 8 respectively.
Answers
Answer:
Answer is 10.62
Step-by-step explanation:
Mode =20+(10-8/20-8-x)*10=34.5
=20/12-x=14.5
=>20 = 174-14.5x
Therefore x =174-20/14.5 = 10.62
Solution :-
Class Frequency
0 - 10 4
10 - 20 8
20 - 30 10
30 - 40 x
40 - 50 8
we know that,
- Mode = l + [(f1 - f0) / (2f1 - f0 - f2)] * h
since mode is given as 34.5 . then, modal class is 30 - 40.
so, we have,
- l = lower limit of modal class = 30
- f1 = frequency of modal class = x
- f0 = previous frequency = 10
- f2 = next frequency = 8 .
- h = size of class = 10 .
Putting all values we get,
→ 34.5 = 30 + [(f - 10)/(2f - 10 - 8)] * 10
→ 34.5 - 30 = [(f - 10)/(2f - 18)] * 10
→ 4.5(2f - 18) = 10(f - 10)
→ 9f - 81 = 10f - 100
→ 10f - 9f = 100 - 81
→ f = 19. (Ans.)
Hence, the missing frequency is 19.
Learn more :-
calculate the median and mode from the following income between (rs)100-200 100-300 100-400 100-500 100-600 no of person...
https://brainly.in/question/23585381
Some students of class X donated for the welfare of old age persons. The contributions are shown in the following distri...
https://brainly.in/question/17314012