Math, asked by lasya23, 8 months ago


Find the missing number in place of blank of following series
3, 22,_,673, 2696, 8093
(a) 133
(b) 143
(d) 134
(c) 156
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I need full process .
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I need a correct process.
.Step by step.explanation I want.

Answers

Answered by mysticd
1

 Given \: sequence : \\3,22, \red{?} , \:673, \:2696, 8093

/* Observe the pattern of the sequence , we get */

  • First term = 3
  • second term = 3 × 7 + 1 = 21 + 1 = 22
  • Third term = 22 × 6 + 2 = 132 + 2 = 134
  • Fourth term = 134 × 5 + 3 = 670 + 3 = 673
  • Fifth term = 673 × 4 + 4 = 2692 + 4 = 2696

Therefore.,

 Option \: \pink { ( d ) } \: is \: correct

•••♪

Answered by kattukuriveera7788
0

Answer:

3*7=21+1=22,,, 22*6=132+2=134,,,,,, 134*5=670+3=673

answer:(d) 134

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