Question

find the missing number in the series 1 , 43 , 161 , 407 ,?
(a)745 (c)614
(c)829 (d)725​

Answer 1

Answer:

Step-by-step explanation:

The given series are 1, 43, 161, 407,

There are two series 1, 161, ?

and 43, 407,

The first pattern is (3²-8), (13² - 8), (23²-8).

The second pattern is (6² + 7), (20² + 7).

:: Missing number (?) = (23² - 8) = 529 - 8

= 521

Hence, missing number (?) = 521

i think option is wrong

Answer 2

The Answer is in Attachment

Hope it Help you