Math, asked by brijbhushan31, 10 months ago

Find the missing number in the series
41 , 12 , 163 , 94 , 365 , 256 , ?​

Answers

Answered by Aradhya3210
5

Answer:

647

Step-by-step explanation:

41+(122)=163+(202)=365+(282)=647

Answered by akshaym72sl
0

Answer:

The number is 647.

Given:

Series: 41 , 12 , 163 , 94 , 365 , 256 , ?​

To Find:

The number in place of ? mark.

Step-by-step explanation:

Let us try find pattern in the number series  41 , 12 , 163 , 94 , 365 , 256 , ?​

First split the series in two parts

i.e.

41 , 12 , 163 , 94 , 365 , 256 , ?​

One series will be: 41, 163, 365, ?

another series will be: 12, 94, 256

Let us first consider series: 41, 163, 365, ?

the difference between consecutive terms is

163 - 41 = 122

365 - 163 = 202

so,

the difference is increasing by 80.

Let us first consider series: 12, 94, 256.

the difference between consecutive terms is

94 - 12 = 82

256 - 94 = 162

here also the difference is increasing by 80.

so,

in the series 41, 163, 365, ?.

the difference between ? and 365 will (202 + 80) = 282

⇒ ? - 365 = 282

⇒ ? = 282 + 365

⇒ ? = 647

Hence, the number in the place of ? is 647.

#SPJ2

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