Question

Find the missing number in the series: 5255, 5306 ,?, 5408, 5459 A) 5057 B)5357 C) 5157 D) 5158

Answer 1

Hey dude...

Let you know the answer for this question...

In question,

The difference between first two numbers , that is between 5255 and 5306 is 51...

The difference between last two numbers , that is 5408 and 5459 is 51...

Show the difference between every immediate Presiding number is 51..

Show the missing number is

5306+51=5357

The option is (b)...

Hope it might will help you more...

☺☺

Answer 2

hєч thєrє✌✌
ᴜʀ ᴀɴꜱ ɪꜱ ʜᴇʀᴇ ----

♥Sequence = An ordered collection of numbers a1 , a2 , a3 ,............
an......is a sequence.

♥Arithmetic progression = A sequence a1,a2,a3,.........,an is called an Arithmetic progression (A.P.) when a2-a1 = a3-a3 =......an -a(n-1) . That means A.P. is a sequence in which each term is obtained by addind a constant d to the preceding term.

♥d = The constant d is called common difference of the A.P .

♥FORMULAS -----
d= a2 - a1
an = a + (n-1 )d
sn = n/2 [2a +( n-1) d]

where
a= first term of the A.P.
d = common difference
n = no of terms
an = nth term of A.p.
sn= sum to nth term

Now come to ur Question-----

ɢɪᴠᴇɴ ---

thє ѕєríєѕ = 5255 ,5306, ? , 5408 , 5459
d = ѕєcσnd tєrm - fírѕt tєrm
= 5306 - 5255
= 51

ѕσ thє ѕєríєѕ íѕ αn ᴀ.ᴩ.

a = 5255
d = 51
an = 5459


a3 = a + 2d
= 5255 + 2( 51)
= 5255 + 102
= 5357

ꜱᴏ ᴜʀ ᴀɴꜱ ɪꜱ ᴏᴩᴛɪᴏɴ ʙ.

☺hσpє ít hєlpѕ u☺

♥fєєl frєє tσ αѕk αnч quєrч♥