Question

Find the missing number in the series- 9,31,73,?,241

Answer 1

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Thanks!

❣ Here is your answer which you are searching for ❣

The first term in the series can be written as

9 = 1^2+2^3

FOLLOW the same procedure

2^2 +3^3

= 31


3^2 +4^3

= 73

Next what's the next series

4^2 +5^3

= 141

The given next series is

5^2 + 6^3

= 241

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@Brainlestuser

Answer 2

$<b>$Your answer !!

=> 9, 31, 73, ?, 241

《《《 Trick used 》》》

$= > 9 = {1}^{2} + {2}^{3} \\ \\ = > 9 = 1 \times 1 + 2 \times 2 \times 2 \\ \\ = > 9 = 1 + 8 \\ \\ = > 9 = 9$
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$= > 31 = {2}^{2} + {3}^{3} \\ \\ = > 31 = 2 \times 2 + 3 \times 3 \times 3 \\ \\ = > 31 = 4 + 27 \\ \\ = > 31 = 31$
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$= > 73 = {3}^{2} + {4}^{3} \\ \\ = > 73 = 3 \times 3 + 4 \times 4 \times 4 \\ \\ = > 73 = 9 + 64 \\ \\ = > 73 = 73$
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$= > ? = {4}^{2} + {5}^{3} \\ \\ = > ? = 4 \times 4 + 5 \times 5 \times 5 \\ \\ = > ? = 16 + 125 \\ \\ = > ? = 141$
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$= > 241 = {5}^{2} + {6}^{3} \\ \\ = > 241 = 5 \times 5 + 6 \times 6 \times 6 \\ \\ = > 241 = 25 + 216 \\ \\ = > 241 = 241$

Hence, your required answer is 141 !!

Thanks !!