Question

find the missing side of a right-angled triangle if
area=20cmsq, height=10cm

Answer 1

Answer:

1/2 × base ×height = 20

1/2 × 10 × base = 20

base = 20/5

base = 4 cm

Answer 2

Area = 20, height =10 cm

Area =1/2 X b X h = 20

b = 20 X 2 /10 = 4 cm

According to Pythagoras theorem

Third side

$\sqrt{10 {}^{2} { + 10}^{2} } = \sqrt{100 + 100}$

$\sqrt{200} = 10 \sqrt{2} cm$

So sides of triangle are 10cm, 4cm and 10 √2cm.

HOPE THIS HELPS YOU !!!