Question

find the missing term in A.p _,8_,_,_, 28​

Answer 1

GIVEN :–

• An A.P. _,8_,_,_, 28.

TO FIND :–

• Missing term = ?

SOLUTION :–

• Here –

➳ a = ?

➳ a + d = 8 ________eq.(1)

➳ a + 2d = ?

➳ a + 3d = ?

➳ a + 4d = ?

➳ a + 5d = 28 ________eq.(2)

• By eq.(2) – eq.(1) :–

⇛ (a + 5d) - (a + d)= 28-8

⇛ 4d = 20

⇛ d = 5

• Using eq.(1) –

⇛ a + 5 = 8

⇛ a = 3

• Hence, The A.P. is 3,8,13,18,23,28.

Answer 2

Answer:

The A.P is 3,8,13,18,23,28,...

Step-by-step explanation:

Question:

Find the missing term in A.P _,8_,_,_, 28

Given:

• A missing term = _,8_,_,_, 28
• $\sf{a_2=8}$
• $\sf{a_6=28}$

To find:

• $\sf{a_1}$
• $\sf{a_3}$
• $\sf{a_4}$
• $\sf{a_5}$

Solution:

$\sf{a_2\:can\:also\:be\:written\:as\:a+d}$

$\sf{a+d=8}$ ____(1)

$\sf{a_6\:can\:also\:be\:written\:as\:a+5d}$

$\sf{a+5d=28}$ ____(2)

Subtracting Equations (1) and (2),

$\sf{a+d-(a+5d)=\:-20}$

$\sf{\cancel{a}+d-\cancel{a}-5d=\:-20}$

$\sf{-4d=\:-20}$

$\boxed{\rm{d = 5}}$

We know that $\sf{a+d=8}$

$\sf{a+5=8}$

$\boxed{\frak{a=3}}$

Therefore,

The A.P is 3,8,13,18,23,28,...