Math, asked by Regineiskyut, 6 months ago

Find the missing value to make the following expressions a perfect square trinomial
1. (x² - 3x) = 0
2. x² - 2x - 8 = 0
3. x² - 13x - 12 = -42
4. 2x² + 7x - 15 =0

Answers

Answered by gunashekhar10
1

Answer:

1.(x²-3x)

=x(x-3)

= x-3=0

Step-by-step explanation:

2.x²-2x-8=0

= x²-2x+4x-8=0

=x(x-2)+4(x-2)

=(x-2)(x+4)

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