Find the missing value to make the following expressions a perfect square trinomial
1. (x² - 3x) = 0
2. x² - 2x - 8 = 0
3. x² - 13x - 12 = -42
4. 2x² + 7x - 15 =0
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Answer:
1.(x²-3x)
=x(x-3)
= x-3=0
Step-by-step explanation:
2.x²-2x-8=0
= x²-2x+4x-8=0
=x(x-2)+4(x-2)
=(x-2)(x+4)
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