.. Find the missing values:
S.No.
Base
Height Area of the Parallelogram
a.
20 cm
246 cm?
Answers
Answer࿐
Find two consecutive odd numbers such that two fifths of the smaller number exceeds two ninths of the larger by 4
Solution :
Let one odd number be ' 2n + 1 '
This is smallest odd number .
Other consecutive odd number be ' 2n + 3 '
This is largest odd number .
A/c , " Two fifths of the smaller number exceeds two ninths of the larger by 4 "
First consecutive smallest odd number :
= 2n + 1
= 2(12) + 1
= 24 + 1
= 25
Second consecutive largest odd number :
= 2n + 3
= 2(12) + 3
= 24 + 3
= 27
Alternative : You may solve this question by taking ' x ' as smallest consecutive odd number and ' x + 2 ' as biggest consecutive odd number .
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Answer:
12.3
Step-by-step explanation:
area of the parallelogram is
area = base ×height
now put the values
246= base ×20
base =246/20
base = 12.3