Question

Find the mistake in my given solution ​

Answer 1

in splitting the number

Answer 2

Answer:

$(x+2\sqrt{5} )(3\sqrt{5}-5 )$

Step-by-step explanation:

$3\sqrt{5} x^{2} +25x-10\sqrt{5} \\\\=>3\sqrt{5} x^{2} +30x-5x-10\sqrt{5} \\\\=>3\sqrt{5} x^{2} +(3\sqrt{5} )(2\sqrt{5} )x -5x-10\sqrt{5}\\\\=>3\sqrt{5} x (x+2\sqrt{5} ) -5(x+2\sqrt{5})\\\\=>(x+2\sqrt{5} )(3\sqrt{5}-5 )$

The mistake in your answer is that you have divided 25x as (15x+10x) but it should be divided as 30x-5x as $(3\sqrt{5})\times (-10\sqrt{5} ) =-150$ but 15 × 10= +150 ≠ -150

30 × -5 = -150