Question

find the mod and argument of​

Answer 1

Step-by-step explanation:

(i+3+2i^2+6i)/(4+6i-2i-3i^2)

=(7i-2+3)/(4+4i+3)

(since i^2 = -1)

= (7i+1)/(4i+7)

multiply numerator & denominator by

(4i-7)

= (7i+1)(4i-7)/{(4i)^2 -(7)^2}

= (28i^2-49i+4i-7)/(-16-49)

= (-35-45i)/(-65)

= (35/65) +(45/65)i

x = 7/13 & y = (9/13)

modulus = √ {(7/13)^2+(9/13)^2}

=√( 130/13^2)= √(10/13)

argument = tan-1{(9/13)/(7/13)}

= tan-1(9/7) = 52.12°