Find the modal use of electricity of the components
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Answer:
65.625
Step-by-step explanation:
Mode = l + h(f1-f0/2f1 - f0 - f2)
Modal class = 60-80
l =60
h = 20
F1 = 68
F0 = 59
F2 = 45
Mode = 60 + 20(68-59/136-59-45)
= 65.625
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