Find the mode
C.I:0-100 10-20 20-30 30-40 40-50 50-60 60-70 70-80
Fre: 7 9 10 16 7 8 15 8
Answers
Answered by
1
The highest frequency of the given data is 16.
therefore, Modal class =30-40
so, fo = 10, f1 = 16 , f2 = 7 , l= 30 and h=10
NOW, mode = l+( f1-fo/2f1-fo-f2) * h
= 30+(16-10/2*16-10-7) * 10
= 30+(6/15)*10
=30+(2/5)*10
=30+2*2
=30+4
=34.
HENCE, mode of the given data is 34.
HOPE IT HELPS YOU .
therefore, Modal class =30-40
so, fo = 10, f1 = 16 , f2 = 7 , l= 30 and h=10
NOW, mode = l+( f1-fo/2f1-fo-f2) * h
= 30+(16-10/2*16-10-7) * 10
= 30+(6/15)*10
=30+(2/5)*10
=30+2*2
=30+4
=34.
HENCE, mode of the given data is 34.
HOPE IT HELPS YOU .
Answered by
0
✌️✌️ hey mate,
The highest frequency of the given data is 16.
therefore,
Modal class =30-40
so,
fo = 10,
f1 = 16 ,
f2 = 7 ,
l= 30
h=10
NOW,
mode = l+( f1-fo/2f1-fo-f2) × h
= 30+(16-10/2*16-10-7) × 10
= 30+(6/15)× 10
=30+(2/5) ×10
=30+2 ×2
=30+4
=34.
HENCE,
Mode of the given data is 34.
thanks....
nice to help you ✌️✌️
The highest frequency of the given data is 16.
therefore,
Modal class =30-40
so,
fo = 10,
f1 = 16 ,
f2 = 7 ,
l= 30
h=10
NOW,
mode = l+( f1-fo/2f1-fo-f2) × h
= 30+(16-10/2*16-10-7) × 10
= 30+(6/15)× 10
=30+(2/5) ×10
=30+2 ×2
=30+4
=34.
HENCE,
Mode of the given data is 34.
thanks....
nice to help you ✌️✌️
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