Question

Find the mode of the following data.

22, 19, 18, 17, 18, 22 , 14, 18

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Answer 1

To find the mode,

it is best to put the numbers in order. Then count how many of each number. A number that appears most often is the mode.

For example as given in image .

according to image it's answer is 7 and 10.

therefore ,

22, 19, 18, 17, 18, 22, 14, 18.

14, 17, 18, 18, 18, 19, 22, 22.

= 14, 17, 18, 19, 22

answer is 18.

the mode of the following is 18.

Answer 2

Basic Concept :-

Mode :-

• Mode is defined as the value that repeat maximum number of times.

Let's solve the problem now!!

Given data is

• 22, 19, 18, 17, 18, 22 , 14, 18

Frequency distribution table is as below :-

$\begin{gathered}\boxed{\begin{array}{c|c} \bf observation & \bf frequency \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf 14 & \sf 1 \\ \\ \sf 17 & \sf 1 \\ \\ \sf 18 & \sf 3\\ \\ \sf 19 & \sf 1\\ \\ \sf 22 & \sf 2 \end{array}} \\ \end{gathered}$

From this table, we concluded that observation 18 repeated thrice.

So,

• Mode of the given data is 18.

Additional Information :-

$\boxed{ \sf \:Mean \: = \: \dfrac{ \displaystyle\sum_{i=1}^n \: x_i}{n} }$

$\boxed{\sf \: Mean = \dfrac{ \sum f_i x_i}{ \sum f_i}}$

$\boxed{ \sf \: Median \: = {\bigg(\dfrac{n + 1}{2} \bigg) }^{th} \: observation \: if \: n \: is \: odd}$

If n is even, then

$\boxed{ \sf \: Median = \dfrac{1}{2}\bigg(\bigg( \dfrac{n}{2} \bigg)^{th} + \bigg(\dfrac{n}{2} + 1 \bigg)^{th} \: \bigg) }$