Question

Find the mode of the following distribution class 100 to 12O,120 to 140,140 to 160, 160 to 180 ,180 to200
frequency 12 14 18 610

Answer 1

li= 140
f1=18
f0=14
f2=6
h=20

$li + \frac{f1 - f0}{2f1 - f0 - f2} \times h$
$140 + \frac{18 - 14}{36 - 14 - 6} \times 20$
$140 + \frac{4}{6} \times 20$
$140 + \frac{40}{3}$
$140 + 1.33$
$141.33$
hence, the mode is 141.33
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