Question

find the mode of the following frequency distribution table


class 0-10 10-20 20-30 30-40 40-50 50-60 60-70


frequency 8 10 10 16 12 6 7
pls fast its very urgent

Answer 1

MODE

hope it helps

MATHS

....

Answer 2

The mode is 36

Step-by-step explanation:

given data  

0-10            8  

10-20          10

20-30          10

30-40          16

40-50          12

50-60          6

60-70           7

here , maximum frequency = 12

modal class = 30-40

h = 10

$f_1 = 16, f_0 = 10, f_2 = 12$

mode = $l+ \left ( \frac{f_1-f_0}{2f_1-f_0-f_2} \right )\times h$

then

$30+ \left ( \frac{16-10}{2(16)-10-12} \right )\times 10\\\\30+ \left ( \frac{6}{32-10-12} \right )\times 10\\\\30+\left ( \frac{6}{10} \right )\times 10\\\\30 + 6 \\\\= 36$

hence , The mode is 36

#Learn more:

If l=3,f1=8,fo=7,f2=2,h=2 then find mode

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