Find the mode of the given data
Marks = 0-20 | 20-40| 40-60| 60-80
frequency=15 | 6 | 18 | 10
Answers
Answer:
Highest frequency 12 , Modal class =40−60
Mode =I+
2f
1
−f
0
−f
2
f
1
−f
0
×h
Where ,
I= lower limit of the modal class =40
f
1
= frequency of modal class =12
f
2
frequency of class after the modal class =6
f
0
frequency of class before the modal class =10
h= class width =20
putting the values in the equation
Mode=50
Step-by-step explanation:
Answer:
51.5
Step-by-step explanation:
The question doesn't look well constructed
Mode = L + [(fm − fm-1)]/[(fm − fm-1) + (fm − fm+1)] × w
where:
L is the lower class boundary of the modal group
fm-1 is the frequency of the group before the modal group
fm is the frequency of the modal group
fm+1 is the frequency of the group after the modal group
w is the group width
=> Mode = 39.5 + {(18-6)}/{(18-6)+(18-10)} × 20
= 39.5 + (12/20) × 20 = 51.5