Question

find the modules (1-i)(1+I)​

Answer 1

Answer:

sorry we didn't have to write

Answer 2

Answer:

Let z=

1−i

1+i

−

1+i

1−i

=

(1−i)(1+i)

(1+i)

2

−(1−i)

2

=

1

2

+1

2

1+i

2

+2i−1−i

2

+2i

=

2

4i

=2i

∴∣z∣=∣2i∣=

2

2

=2