find the modules of and conjugate of the following complex number z= -2+i7
Answers
Answer:
If z = a + ib, then the complex conjugate of z is a - ib.
Given Complex Number (z): - 2 + 7i
Conjugate of a complex number is ( -z ).
⇒ ( -2 - 7i )
⇒ -2 - 7i
Therefore the conjugate of the given complex number -2 - 7i.
Modulus of a complex number z which is represented as a + bi is given as:
where, 'a' is the numerical value of real part and 'b' is the numerical value of complex part .
According to the given complex number:
a = -2 , b = 7
⇒ |z| = √(-2)² + (7)²
⇒ |z| = √(4) + (49)
⇒ |z| = √53
Hence the modulus of the complex number is √53.
Topic : Complex number
Explanation:
We are asked to find the conjugate and modulus of the given complex number.
Conjugate of a complex number is equal to the complex number with same real part but imaginary part of opposite sign.
For a complex number , it's conjugate is given by . (Conjugate of a complex number z is denoted by z bar.)
We have,
z = -2 + 7i
So it's conjugate is given by,
Modulus of a complex number is it's distance in the argànd plane from origin.
In order to find the modulus (or magnitude) of a complex number z = a + ib, we may use the formula where |z| is the magnitude of complex number.
We have,
z = -2 + 7i
Here,
- Re(z) = a = -2
- Im(z) = b = 7
Therefore the modulus of this complex number is given by,
So we can conclude that conjugate of complex number is -2 - 7i and it's modulus is √53.
Additional information:
There is one more method to find the magnitude of complex number.
Therefore the magnitude of given complex number can also be given by,
Refer to the attachment to know graphical presentation of conjugate of complex number. [Picture source - Wikipedia]