Find the modulua and amplitude of 1+iroot3
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For x+ iy, modulus = √(x^2+y^2)
Amplitude = tan^-1 (y/x)
So, mod of 1+i√3 = √(1+3) = 2
Amplitude = tan^-1(√3/1) = 60 degrees
Amplitude = tan^-1 (y/x)
So, mod of 1+i√3 = √(1+3) = 2
Amplitude = tan^-1(√3/1) = 60 degrees
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