find the modulus (4+3i)-(2+5i)
Answers
Answered by
0
Answer:
it is a sample hope by this you may get your answer
Step-by-step explanation:
(3-4i)(4+3i)
12+9i-16i+12
24-7i
√24^2+7^2
√576+49
√625
25
Answered by
0
Answer:
2√2
Step-by-step explanation:
z = (4 + 3i) - (2 + 5i)
z = 4 + 3i - 2 - 5i
z = 2 - 2i
Comparing with z = x + yi,
x = 2 ; y = -2
∣z∣= √(x² + y²)
∣z∣ = √(2)² + (-2)²
∣z∣ = √(4 + 4)
∣z∣ = √8
∣z∣ = 2√2
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