Question

Find the modulus and argument of the complex number 2+2√3 i .​

Answer 1

Step-by-step explanation:

1. ww know that
2. $r = \sqrt{ {x + y}^{2} }$
3. so ,r= under root 2^2+2root3^2 = under root 4+12=16 =+-4
4. now , alpha =tan^- |y/x| so alpha = tan^- |2roor3/2 =roor3 .I.e tan^- root3= tan^-tan60° =pie/6
5. thus , the no lies in 1st quadrant theta = alpha = pie/6
6. the modulus = +-4,and the argument = pie /6 Ans .