Question

Find the modulus and argument of the complex number and hence express it in polar form: -4+4√3i.​

Answer 1

Answer:

i can't understand this question

Answer 2

Answer:

The required polar form is

$8( \cos \frac{2\pi}{3} + i \: \sin \frac{2\pi}{3} )$

Step-by-step explanation:

-4= r cos theta

4 root 3 = r sin theta

Squaring and adding ,we get

16+48 = r square cos square theta + r square sin square theta

64 = r square ( cos sq theta + sin sq theta )

64 = r square ( 1)

r square = 64

r= 8

theta is in second quadrant ,

cos theta = -1/2 , sin theta = root 3/2

$theta = \pi - \frac{\pi}{3} = \frac{2\pi}{3}$

Polar form is

$8( \cos \frac{2\pi}{3 } + i \sin\frac{2\pi}{3} )$

HOPE..!!! IT HELPSSS!!!!