Question

Find the modulus and principal argument of -2i

Answer 1

Answer:

modulus of 0-2i is

Step-by-step explanation:

let z = 0-2i

z bar=

$\sqrt{(real) {}^{2} } + \sqrt{(imaginary) {}^{2} }$

z bar =

$\sqrt{(0) {}^{2} } + \sqrt{( - 2) { }^{2} }$

z bar =

$\sqrt{4}$

z bar = 2

hope it helps u