Question

Find the modulus are arguments z= 3√ 3 ​ + 3i

Answer 1

Step-by-step explanation:

z=−

3

+i

Modulus

∣z∣=

(−

3

)

2

+1

2

=

3+1

=2

∣z∣=2

Argument

θ=tan

−1

a

b

=tan

−1

−

3

1

=−30

∴θ=180−30=150

θ=150×

180

π

θ=

6

5π