Math, asked by prajwal7440, 5 months ago

find the modulus of 1/1+i​

Answers

Answered by SrijanShrivastava
1

 z =  \frac{1}{1 +  \sqrt{ - 1} }

z =  \frac{1 -  \sqrt{ - 1} }{ {1}^{2}  -  {( \sqrt{ - 1}) }^{2} }

z =  \frac{1 -  \sqrt{ - 1} }{2}

 \implies z =  \frac{1}{2}  -  \frac{1}{2} i

 \therefore  |z|  =  \sqrt{( \frac{1}{2} ) ^{2} +  {( \frac{1}{2} )}^{2}  }

 \underline{ |z|  =  \frac{ \sqrt{2} }{2} }

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