find the modulus of 2/3-4i
Answers
Answered by
0
If z = a + ib is any complex number then modulus z = |z| = √(a² + b²)
Given that z = 2/3 - 4i
So modulus of z = | z | = √[(2/3)² + (-4)² ] [ since a = 2/3 and b = - 4 ]
| z | = √[(4/9)+16]
= √(4+144)/9
= √(148/9)
= 2(√37)/3
Similar questions