Find the modulus of (3-2i)(2+3i)/(1+2i)(2-i) Please answer only if u know the right answer...please help me
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Step-by-step explanation:
Solution
= (32i) (2 + 3i) 6 + 9i - 4i + 6
= ___________
= (1+2i) (2 - i) 2-i + 4i + 2
= 12 + 5i
= 4 + 3i
= (12 + 5i) (4-3i)
= 16 9 48 36i+20i + 15 5
= 63 161
= 5
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