find the modulus of i/(1-i)
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Answer:
Let z=1+iz=1+i
then z¯=1−iz¯=1−i
⟹|z|2=zz¯⟹|z|2=zz¯
⟹|z|2=(1+i)(1−i)⟹|z|2=(1+i)(1−i)
⟹|z|2=1+1=2⟹|z|2=1+1=2
⟹|z|=2–√
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